1.35s^2-10=0

Solution for 1.35s^2-10=0 equation:

1.35s^2-10=0

a = 1.35; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·1.35·(-10)
Δ = 54
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54}=\sqrt{9*6}=\sqrt{9}*\sqrt{6}=3\sqrt{6}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{6}}{2*1.35}=\frac{0-3\sqrt{6}}{2.7}
=-\frac{3\sqrt{6}}{2.7}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{6}}{2*1.35}=\frac{0+3\sqrt{6}}{2.7}
=\frac{3\sqrt{6}}{2.7}
$